Binary Search (LeetCode)
Given an array of integers nums
which is sorted in ascending order, and an integer target
, write a function to search target
in nums
. If target
exists, then return its index. Otherwise, return -1
.
You must write an algorithm with O(log n)
runtime complexity.
Example 1:
Input: nums = [-1,0,3,5,9,12], target = 9 Output: 4 Explanation: 9 exists in nums and its index is 4
Solution(Java)
class Solution {
public int search(int[] nums, int target) {
int start=0, end=nums.length-1;
while(start<=end){
int mid= start+(end-start)/2;
if(target<nums[mid])
end=mid-1;
else if(target>nums[mid])
start=mid+1;
else
return mid;
}
return -1;
}
}
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