Final Value of Variable After Performing Operations (LeetCode)

 There is a programming language with only four operations and one variable X:

• ++X and X++ increments the value of the variable X by 1.
• --X and X-- decrements the value of the variable X by 1.

Initially, the value of X is 0.

Given an array of strings operations containing a list of operations, return the final value of X after performing all the operations.

 

Example 1:

Input: operations = ["--X","X++","X++"]
Output: 1
Explanation: The operations are performed as follows:
Initially, X = 0.
--X: X is decremented by 1, X =  0 - 1 = -1.
X++: X is incremented by 1, X = -1 + 1 =  0.
X++: X is incremented by 1, X =  0 + 1 =  1.

Solutions:

class Solution {
    public int finalValueAfterOperations(String[] operations) {
        int val=0;
        for(int i=0; i<operations.length; i++){
         if(operations[i].charAt(1)=='+')
             val++;
         else
             val--;
        }
        return val;
    }
}