Final Value of Variable After Performing Operations (LeetCode)
There is a programming language with only four operations and one variable X : ++X and X++ increments the value of the variable X by 1 . --X and X-- decrements the value of the variable X by 1 . Initially, the value of X is 0 . Given an array of strings operations containing a list of operations, return the final value of X after performing all the operations . Example 1: Input: operations = ["--X","X++","X++"] Output: 1 Explanation: The operations are performed as follows: Initially, X = 0. --X: X is decremented by 1, X = 0 - 1 = -1. X++: X is incremented by 1, X = -1 + 1 = 0. X++: X is incremented by 1, X = 0 + 1 = 1. Solutions: class Solution { public int finalValueAfterOperations(String[] operations) { int val=0; for(int i=0; i<operations.length; i++){ if(operations[i].charAt(1)=='+') val++; else val--; } return val